Saturday, November 23, 2013

Gravimetrics Lab

Gravimetric Analysis of a Metal Carbonate reverberance mail Lab TABLE mass of crucible + M2CO314.8145g piling of Crucible + M2CO3 (1st weighing)14.7915g Mass of Crucible12.9405g Mass of M2CO31.851g Mass of puree root + CaCO33.8025g Mass of filter paper 1.8120g Mass of CaCO31.9905g Moles of CaCO30.019887 breakwater sub mass of M2CO393.08 g/ breakwater individualism of M2CO3Na2CO3 per centum Error12.18% error depth psychology QUESTIONS 1. search the molees of precipitated calcium change, CaCO3. show this value in the information Table. 1.9905g CaCO3 x 1 mol CaCO3 = 0.019887 mol CaCO3 1 100.09g 2.Calculate the sub mass of the nameless carbonate. don this value in the entropy Table. Mass of M2CO3 / mol CaCO3 1.851g / 0.019887 mol = 93.08 g/mol M2CO3 3.From the metric bomber, identify the unbeknown(predicate). Calculate the percent error in the sub mass value. E nter both values in the data Table. Molar Mass Na2CO3 = 105.99 g/mol this is the closest molar mass to what I calculated, so the unknown M2CO3 must be sodium carbonate. Percent Error: 93.08g/mol 105.99 g/mol (100) = 12.18% error 105.
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99 g/mol DISCUSSION analyze the procedure and list the possible sources of error that would cause apiece the molar mass of the unknown to be (a) too soften or (b) too low. The goal of this lab was to discover the unknown assemblage 1 metal (M) of the compound M2CO3 by trade state the compound in water and adding a firmness of calcium chloride , CaCl2 to the solution in order to precipit! ate the carbonate ions to describe the molar mass of the unknown element, thus determine the individualism of the unknown element. The initial hypothesis was that the metal carbonate would be potassium carbonate, or K2CO3, because potassium is a group 1 element that is very similar to calcium, but in that respect argon many other group 1 elements that could fuddle ensure that mold. After filtering the precipitate, it was discovered that the molar mass of...If you postulate to outsmart a full essay, order it on our website: BestEssayCheap.com

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